Matematika
n-tojo laipsnio šaknimi iš skaičiaus a atrodo taip: . Kai n=2 tada šaknies rodiklio nerašome ir šį pavidalą vadiname kvadratine šaknimi.
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![\sqrt[n]{a}](http://s.wordpress.com/latex.php?latex=%5Csqrt%5Bn%5D%7Ba%7D&bg=ffffff&fg=000000&s=1 "\sqrt[n]{a}")
![\sqrt[n]{a^n}=a](http://s.wordpress.com/latex.php?latex=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da&bg=ffffff&fg=000000&s=1 "\sqrt[n]{a^n}=a")
![(\sqrt[n]{a})^n=a](http://s.wordpress.com/latex.php?latex=%28%5Csqrt%5Bn%5D%7Ba%7D%29%5En%3Da&bg=ffffff&fg=000000&s=1 "(\sqrt[n]{a})^n=a")
![\sqrt[2n]{a^2n}= \arrowvert a \arrowvert](http://s.wordpress.com/latex.php?latex=%5Csqrt%5B2n%5D%7Ba%5E2n%7D%3D%20%5Carrowvert%20a%20%5Carrowvert&bg=ffffff&fg=000000&s=1 "\sqrt[2n]{a^2n}= \arrowvert a \arrowvert")
![\sqrt[n]{ab}=\sqrt[n]{a} \cdot \sqrt[n]{b}](http://s.wordpress.com/latex.php?latex=%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%20%5Ccdot%20%5Csqrt%5Bn%5D%7Bb%7D&bg=ffffff&fg=000000&s=1 "\sqrt[n]{ab}=\sqrt[n]{a} \cdot \sqrt[n]{b}")
![\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}](http://s.wordpress.com/latex.php?latex=%20%5Csqrt%5Bn%5D%7B%5Cfrac%7Ba%7D%7Bb%7D%7D%3D%5Cfrac%7B%5Csqrt%5Bn%5D%7Ba%7D%7D%7B%5Csqrt%5Bn%5D%7Bb%7D%7D&bg=ffffff&fg=000000&s=2 "\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}")
![(\sqrt[n]{a})^m=\sqrt[n]{a^m}](http://s.wordpress.com/latex.php?latex=%28%5Csqrt%5Bn%5D%7Ba%7D%29%5Em%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D&bg=ffffff&fg=000000&s=1 "(\sqrt[n]{a})^m=\sqrt[n]{a^m}")
![\sqrt[m]{\sqrt[n]{a}}=\sqrt[m \cdot n]{a}](http://s.wordpress.com/latex.php?latex=%5Csqrt%5Bm%5D%7B%5Csqrt%5Bn%5D%7Ba%7D%7D%3D%5Csqrt%5Bm%20%5Ccdot%20n%5D%7Ba%7D&bg=ffffff&fg=000000&s=1 "\sqrt[m]{\sqrt[n]{a}}=\sqrt[m \cdot n]{a}")
![\sqrt[m]{a^n}=\sqrt[m \cdot k]{a^{n \cdot k}}](http://s.wordpress.com/latex.php?latex=%5Csqrt%5Bm%5D%7Ba%5En%7D%3D%5Csqrt%5Bm%20%5Ccdot%20k%5D%7Ba%5E%7Bn%20%5Ccdot%20k%7D%7D&bg=ffffff&fg=000000&s=1 "\sqrt[m]{a^n}=\sqrt[m \cdot k]{a^{n \cdot k}}")
